How to Replace Square Brackets From A String In Groovy?

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To replace square brackets from a string in Groovy, you can use the replaceAll() method with a regular expression. You can use the following code snippet:

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def stringWithSquareBrackets = "[Hello, World]"
def stringWithoutSquareBrackets = stringWithSquareBrackets.replaceAll(/\[|\]/, "")

println stringWithoutSquareBrackets // Output: Hello, World


In this code, the replaceAll() method is used with a regular expression /\[|\]/ to match both opening [ and closing ] square brackets, and replacing them with an empty string. This will effectively remove the square brackets from the original string.

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What is the Groovy script for replacing square brackets in a string?

Here is an example Groovy script that replaces square brackets "[" and "]" in a string with parentheses "(" and ")":

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def originalString = "[Hello, world!]"
def modifiedString = originalString.replaceAll(/\[/, "(").replaceAll(/\]/, ")")

println modifiedString


This script will output "(Hello, world!)" as the modified string.


How to replace square brackets only at the beginning or end of a string with Groovy?

You can use the replaceAll method in Groovy to replace square brackets only at the beginning or end of a string. Here's an example:

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def originalString = "[Hello, World]"
def modifiedString = originalString.replaceAll(/^\[|\]$/, '')
println modifiedString


In this example, the replaceAll method is used with a regular expression pattern ^\[|\]$ that matches square brackets at the beginning (^\[) or end (\]$) of the string. The replacement string '' is used to remove the square brackets.


This will result in Hello, World being printed to the console.


How to replace square brackets with a regular expression in Groovy?

In Groovy, you can use the replaceAll method along with a regular expression to replace square brackets.


Here's an example code snippet that demonstrates how to replace square brackets with an empty space using regular expression in Groovy:

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def inputString = "[Hello] [world] [123]"
def outputString = inputString.replaceAll(/\[|\]/, '')

println outputString


In this example, the regular expression /\[|\]/ is used to match both opening [ and closing ] square brackets. The replaceAll method then replaces all occurrences of square brackets with an empty space.


When you run this code, the output will be:

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Hello world 123


You can modify the regular expression pattern as needed to match different patterns of square brackets for replacement.


How to replace square brackets in nested strings with Groovy?

You can use the replaceAll method in Groovy to replace square brackets in nested strings. Here is an example code snippet that demonstrates how to do this:

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def input = "[Hello [World]]"

def result = input.replaceAll(/\[|\]/) { match ->
    if (match == '[') {
        '('
    } else {
        ')'
    }
}

println result


This code will replace all square brackets in the input string with parentheses, including the nested square brackets. The output of this code snippet will be:

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(Hello (World))



What is the fastest way to replace square brackets in Groovy?

One of the fastest ways to replace square brackets in Groovy is to use the replaceAll() method with regular expressions. Here's an example:

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String originalString = "This is [a] test";
String replacedString = originalString.replaceAll("[\\[\\]]", "");

println replacedString; // Output: This is a test


In this example, the replaceAll() method is used to replace all occurrences of square brackets [ and ] with an empty string. The regular expression [\\[\\]] is used to match both square brackets. This approach is efficient and concise for replacing square brackets in a string in Groovy.

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