How to Extract Relative Path From A Url In Postgresql?

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In PostgreSQL, you can extract the relative path from a URL using the regexp_replace function along with a regular expression pattern. You can achieve this by defining a regular expression pattern that matches the domain part of the URL and then replacing it with an empty string to extract the relative path. For example, if you have a URL like https://www.example.com/path/to/file, you can use the regexp_replace function to extract the relative path path/to/file by removing the https://www.example.com part of the URL. This is a simple and effective way to extract the relative path from a URL in PostgreSQL.

What is the best approach to extract the relative path from a URL in PostgreSQL?

One approach to extract the relative path from a URL in PostgreSQL is to use a combination of string functions and regular expressions. Here is a sample query that demonstrates how this can be done:

SELECT regexp_replace(url, E'^https?://[^/]+', '') AS relative_path FROM your_table_name;

In this query, the regexp_replace function is used to remove the protocol and domain part of the URL, leaving only the relative path. The regular expression E'^https?://[^/]+' matches the protocol (http or https) and domain part of the URL.

You can replace your_table_name with the actual name of your table and url with the column containing the URLs. This query will return the relative path of each URL in the specified column.

How to fetch the directory path portion of a URL in PostgreSQL?

To fetch the directory path portion of a URL in PostgreSQL, you can use the regexp_replace function along with a regular expression. Here is an example query to achieve this:

SELECT regexp_replace('https://www.example.com/path/to/page', '^(https?://[^/]+)(/.*)$', '\1') AS directory_path;

In this query:

• '^https?://[^/]+ matches the protocol and domain portion of the URL
• (.*)$ matches the remaining path portion of the URL
• '\1' in the regexp_replace function replaces the entire URL with just the protocol and domain portion, effectively fetching the directory path.

You can adjust the regular expression pattern according to your specific requirements or variations in the URL structure you are working with.

What is the correct syntax to extract the relative path from a URL in PostgreSQL?

To extract the relative path from a URL in PostgreSQL, you can use the regexp_replace function with a regular expression. Here is an example:

SELECT regexp_replace('https://example.com/path/to/resource', 'https?://[^/]+', '');

This query will return /path/to/resource, which is the relative path from the URL https://example.com/path/to/resource. The regular expression used here matches the pattern https?://[^/]+ which finds the scheme and domain of the URL and replaces it with an empty string, leaving only the relative path.